Challenge Your Exam Readiness With Our Free ATI TEAS Practice Questions

Convert the concentration to mg per mL, then scale to the ordered dose. From 125 mg/5 mL, divide both numbers by 5 to get 25 mg/mL. Volume required (=\frac{\text{ordered dose}}{\text{concentration}}): (300\ \text{mg} \div 25\ \text{mg/mL} = 12\ \text{mL}). Thus, answer B. Check each distractor: A (10 mL) would provide only (10 \times 25 = 250) mg (underdose). C (15 mL) would deliver (375) mg (overdose). D (20 mL) equals (500) mg (significant overdose). For TEAS dosage problems, write the ratio as a proportion to prevent inversion errors:

(\frac{125\ \text{mg}}{5\ \text{mL}} = \frac{300\ \text{mg}}{x\ \text{mL}}\Rightarrow 125x = 1500 \Rightarrow x = 12\ \text{mL}).

A quick reasonableness test helps: because 300 mg is a bit more than twice 125 mg, expect a bit more than 2 × 5 mL = 10 mL—specifically 12 mL. Keeping units visible (mg cancel, leaving mL) safeguards against common setup mistakes and supports safe clinical calculation practices.