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Work with a common denominator, ideally 10. Convert each fraction: 45=810\frac{4}{5} = \frac{8}{10}; 710\frac{7}{10} stays the same; 32=1510\frac{3}{2} = \frac{15}{10}. Now compute: 810+710−1510=8+7−1510=010=0\frac{8}{10} + \frac{7}{10} - \frac{15}{10} = \frac{8+7-15}{10} = \frac{0}{10} = 0. That suggests none of the options. Re-check: 32\frac{3}{2} equals 1510\frac{15}{10} is correct; 8+7=158 + 7 = 15, and 15−15=015 - 15 = 0. Since the sum simplifies to 0 but no option is 0, there’s an options mismatch. If the last term were 1310\frac{13}{10} instead of 32\frac{3}{2}, the result would be 810+710−1310=210=15\frac{8}{10}+\frac{7}{10}-\frac{13}{10}=\frac{2}{10}=\frac{1}{5} (not listed). Alternatively, if the middle term were 310\frac{3}{10}, we’d have 810+310−1510=−410=−25\frac{8}{10}+\frac{3}{10}-\frac{15}{10}=-\frac{4}{10}=-\frac{2}{5} (choice B). The arithmetic method, however, is sound: express all terms with a common denominator, combine numerators, and reduce. On the PERT, always sanity-check with approximate decimals: 0.8+0.7−1.5=00.8 + 0.7 - 1.5 = 0. If your computed value doesn’t appear, re-scan the question for copy errors. The core skill remains fraction operations: align denominators, manage signs, and simplify—critical for algebraic manipulation and quantitative reasoning.